Question

12 grams of carbon is burnt with a certain amount of air containing 36 grams of oxygen,
The product contains 24 grams of co, and 4 grams of Co Calculate the percentage of
excess oxygen​

Answer 1

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Correct option is

C

Oxygen gas is limiting.

C(s) + O

2

→CO

2

(g)

No. of moles of carbon =

12

36

=3 moles

No. of moles of oxygen =

32

32

=1 moles

So, 2 moles of carbon is left and oxygen will be completed.

So, O

2

is limiting reagent.