Question

12. HCF of two numbers is 113 their LCM is 56952. If one of the number is 904 then the other number is *
1 point
​

Answer 1

Answer :

The required number is 7119

Step-by-step explanation :

To Find :

• The other number ......(?)

Given that, the HCF of two numbers is 113 their LCM is 56952.

One number is 904

We know that,

H.C.F × L.C.M = First number × Second Number

Therefore, By putting the values,

» 113 × 56952 = 904 × 2nd number

» Second number = ( 113*56952 ) / 904

» = 6435576 / 904

» = 7119

Therefore, the second number is 7119

Now, Verification :

H.C.F × L.C.M = First number × Second Number

By putting the values,

» 113 × 56952 = 904 × 7119

» 6435576 = 6435576

L.H.S = R.H.S

Hence, Verified !

Answer 2

$</p><p>solution :- \\ \\ \\ here \: we \: hve \: to \: find \: the \: other \: number\\ \\ \\ </p><p></p><p>we \: know :- \\ \\ h.c.f \times l.c.m \: \: first \: number \times second \: number\\ </p><p></p><p>the \: full \: form:- \\ l.c.m= least \: commo \: factor \\ \bold{h.c.f} = high \: commom \: factor\\ \\ \longmapsto \tt we \: putting \: the \: values \\ \longmapsto \tt \: 113 \times 56952 = 904 \times 2number \\ \\ \longmapsto \tt </p><p>second \: number :- \\ \longmapsto \tt (133 \div 56952) \div 904 \\ \\ </p><p> = 7119:-</p><p> \\ there \: fore \: the \: second \: number \: is \: 7119 \\ \\ now\\ \\ \longmapsto \tt \: h.c.f \times l.c.m \\ \longmapsto \tt \: first \: number \times second \: number \\ \\ </p><p></p><p>we \: putting \: the \: values:- \\ \longmapsto 113 \times56952 = 904 \times 7119 \\ </p><p></p><p></p><p></p><p>6435576 = 6435576 </p><p>$

https\\brainly.in\\question\\5993730264