Question

12) How many grams of common salt
(NaCl) will be formed when 11.5gm of
sodium (Na) reacts with 35.5grn of
chlorine gas(Cl)? Atomic weight of
sodium is 23 and that of chlorine gas is
71.​

Answer 1

Answer:

35.5grams

Explanation:

The reaction is: 2Na+Cl

2

→2NaCl

23 gm of sodium= 1 mole

Moles of sodium chloride=

58.5

58.5

=1

So, one mole of Na will react with 0.5 mole =0.5×71=35.5 gm Cl

2