Math, asked by tapu3333, 1 month ago

12
(i) (3x - 1)2 - (3x - 2) (3x + 1)​

Answers

Answered by aasthavm2005
2

Step-by-step explanation:

(3x-1)^2 - (3x-2)(3x+1)

= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)

= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2

= -3x + 3

(3x-1)^2 - (3x-2)(3x+1)

= 9x^2 - 6x + 1 - (9x^2 + 3x - 6x -2)

= 9x^2 - 6x + 1 - 9x^2 - 3x + 6x + 2

= -3x + 3

If this was an equation (3x-1)^2 - (3x-2)(3x+1) = 0,

in that case we can find the solution of this equation by

-3x + 3 = 0

x = 1

Answered by Anonymous
3

Answer:

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