Question

12. If 2 is a root of a equation x2 + ax + 12 = 0, and the quadratic

equation x2 + ax + q = 0, has equal roots, find q.​

Answer 1

Step-by-step explanation:

your answer is above attachment

Answer 2

Answer:

q = 12

Step-by-step explanation:

we have the root 2, so we can simply put "x=2" in the equation

${x}^{2} + ax + 12 = 0$

after putting the value of x, i.e. "2", we get,

${2}^{2} + a(2) + 12 = 0 \\ 4 + 2a + 12 = 0 \\ 2a + 16 = 0 \\ 2a = - 16 \\ a = \frac{ - 16}{2} \\ a = - 8$

now, we have the value of x, and a.

$x = 2 \\ a = - 8$

we can simple put this formula in the equation

$x ^{2} + ax + q = 0$

we get,

${2}^{2} + (-8)(2) + q = 0 \\ 4 - 16 + q = 0 \\ - 12 + q = 0 \\ q = 12$

q=12 is the correct answer.

we could simple come to this conclusion by comparing the 2 equations

x2 + ax + 12 = 0 and x2 + ax + q = 0.

since these 2 equations have same roots an are also the same equations, so we could simply compare and get the answer q=12

but this wouldn't be worth more than half marks so I explained it in long with worth 3 marks atleast

pls mark as brainliest. Thanks :)