Question

12. If 2sin²0 - cos0 = 2, then find the value of 0.​

Answer 1

Step-by-step explanation:

hi see

question some what mistake

2sin^2-cos^2=2

cos^2=1-sin^2

2sin^2-(1-sin^2)

3sin^2-1=2

sin^2=1

teta

=90

Answer 2

Answer:

$\huge{\boxed{\rm{\red{Ѳ=90°}}}}$

Step-by-step explanation:

Given equation is

2 sin²Ѳ - cos Ѳ=2

(Sin²A+Cos²A=1)

=>2 (1-Cos²Ѳ) - cos Ѳ=2

=> 2-2Cos²Ѳ-CosѲ=2

=> 2-2Cos²Ѳ-CosѲ-2=0

=>-2Cos²Ѳ-CosѲ=0

=>-(2Cos²Ѳ+CosѲ)=0

=>2Cos²Ѳ+CosѲ =0

=>CosѲ =0 or Cos Ѳ-1=0

=>CosѲ =Cos 90° or Cos Ѳ=1

=>CosѲ =Cos 90° or Cos Ѳ= Cos 0°

Ѳ=90° or 0°

If Ѳ is zero above equation can not be formed

therefore , Ѳ=90°