Question

12. If 2x – 3y = 10 and xy = 16; find the value of
8x3 - 27y3.​

Answer 1

3880

Step-by-step explanation:

2x-3y=10

so (2x-3y)^3=10^3

8x^3-3×2x×3y (2x-3y)-27y^3=1000

8x^3-27y^3=1000+18×16×10.given (xy=10

8x^3-27y^3=1000+2880=3880