Question

12. If 3x - 4y = 5 and xy = 3, find : 27x* - 64y.
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Answer 1

Answer:

27x-64y

3x^3-4y^3 ( acube and bcube identity)

[3x-4y]^3=3x^3-4y^3-3*3x*4y{3x-4y}

5^3=27x-64y-36xy{5}

125=27x-64y-108*5

125+540=27x-64y

665=27x-64y

Step-by-step explanation:

hope it helps you:)