Question

12. If 5th and 6th terms of an A.P. are respectively
6 and 5, find the 11th term of the A.P.​

Answer 1

Hii

you are welcome in my ans

tn term of AP = a + n(n-1)d

a = a

n=5

tn=6

6 = a + 5*4*d

6=a + 20d-----(1

n =6

tn=5

a=a

5 = a + 6*5*d

5=a+30d------(2

putting the value of a in ---(2 from ---(1

6 = 5 - 30d + 20d

d = 11/10

so

a = 5 - 33 =-28

now

t11 = -28 + 11*10*11/10

t11= -28+121

t11= 93

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Hope it may helps you