12. If a step up transformer have turn ratio 5, frequency50 Hz root mean square value of potentialdifference on primary 100 volts and the resistanceof the secondary winding is 500 S2 then the peakvalue of voltage in secondary winding will be (theefficiency of the transformer is hundred percent)(1) 500 V2(2) 10/2(3) 50 V2(4) 2012
Answers
The peak value of voltage in secondary winding will be 500√2.
Explanation:
=> According to the formula of transformer,
Vp /Vs = Np / Ns
Turn ratio Primary = Np
Turn ratio Secondary = Ns
Voltage Primary = Vp
Voltage Secondary = Vs
=> Now root mean square voltage:
Vrms = Vp/√2
Vp = Vrms *√2
Vp = 100√2
=> By placing all the given value in transformer formula, we get
Vp / Vs = Np / Ns
100√2 / Vs = 1/5
Vs =100√2 * 5
Vs = 500√2
Thus, the peak value of voltage in secondary winding will be 500√2.
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