Math, asked by bonalakinnera, 5 months ago

12. If a =
 {2}^{3 }  \times 3
b = 2x3x5, c =
 {3}^{n}  \times 5
LCM
(a, b, c) = 23x32x5, then n =
with​

Answers

Answered by lalitnit
0

a =  {2}^{3} \times 8 = 64

b = 2 \times 3 \times 5 = 30

c =  {3}^{n} \times 5

LCM = 23*32*5 = 3680

 {3}^{n - 1}  =  \frac{3680}{960}  =  \frac{46}{7}

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