Question

12. If in ΔABC, C = 90°, then sin (A + B) =​

Answer 1

Step-by-step explanation:

s(A+B)=sinA.cosB.sinBCosA

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Answer 2

Answer:

Given:-

∆ABC , C= 90°

To Find value of,

sin (A+B)= ?

Solution:-

Sum of all angles of triangles is 180°

Hance ,

∠A + ∠ B + ∠C = 180°

∠A +∠B + 90° = 180° ( given ∠C = 90°)

∠A + ∠B = 180° -90°

∠A + ∠B = 90°

Now,

sin(a+b) = sin 90°

So,

sin (a+b) = 1