Question

12. If k-1, k + 3 and 3k - 1 are three consecutive terms of a AP, find the value of k.​

Answer 1

hope it is correct .Thanks

Answer 2

Answer:

For the terms being consecutive terms of an AP,

k+3-(k-1)= 3k-1-(k+3)=common difference

2= 3k-1-k-3

= 2k-4

2k= 2+4

2k=8

k=4

Step-by-step explanation: