Question

12. If tan2 45°-cos2 30°= xsin 45º cos 45º,
then find the value of x.​

Answer 1

Answer:

tan^245°-cos^230°=xsin45°cos45°

=> (1)^2-(√3/2)^2=x.1/√2.1/√2

=> 1-3/4=x.1/2

=> 1/4=x/2

=> x=1/2

Answer 2

12. If tan2 45°-cos2 30°= xsin 45º cos 45º,

then find the value of x.