Question

12. If the coordinate of the mid-points of the sides of a triangle are (1,1).
(2,-3) and (3, 4) its centroid is :
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Answer 1

Given :coordinates of triangles are let :a (1,1),b (2,-3)andc (3,4)...

then centroid=(x1+x2+x3)/3 and (y1+y2+y3)/3

=(1+2+3)/3, (1-3+4)/3

=6/3,-6/3

=2,-2

Answer 2

Answer:

Centroid of triangle = ((x1 + x2 + x3)/3 , (y1 + y2 + y3)/3)

= ((1 + 2 + 3)/3 , (1 - 3 + 4)/3)

= (2, 2/3)

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