Question

12. If the distance between the point (x,2) and (3,4) is 2. Find the value
(
of x'​

Answer 1

Answer:

3

Step-by-step explanation:

distance= √[(x2-x1)^2+(y2-y1)^2]

the distance between the point (x,2) and (3,4) is 2.

2= √[(x-3)^2+(2-4)^2]

squaring on both sides

4= (x-3)^2+(2-4)^2

4= (x-3)^2+4

(x-3)^2 = 0

(x-3)= 0

X = 3