12. If the distance between the point (x,2) and (3,4) is 2. Find the value
(
of x'
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Answer:
3
Step-by-step explanation:
distance= √[(x2-x1)^2+(y2-y1)^2]
the distance between the point (x,2) and (3,4) is 2.
2= √[(x-3)^2+(2-4)^2]
squaring on both sides
4= (x-3)^2+(2-4)^2
4= (x-3)^2+4
(x-3)^2 = 0
(x-3)= 0
X = 3
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