Question

12. If the product of two numbers is 4032 and their HCF is 12, find their LCM.
13. The HCF and LCM of two numbers are 9 and 270 respectively. If one of the
numbers is 45, find the other number.
14. Find the HCF of 180 and 336. Hence, find their LCM.
15. Can two numbers have 15 as their HCF and 110 as their LCM? Give reason to
justify your answer.





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Answer 1

Answer:

12. 336

13. 54

Step-by-step explanation:

12. we know that, Product of two numbers = HCF × LCM

 4032 = 12  × LCM

LCM =  4032 /12

        = 336

13. Product of two numbers = HCF × LCM

x*45 = 9*270

x = 9×270/45

x = 54

Answer 2

Answer:

12.given

product of two number=4032

HCF=12

solution

product of two numbers= HCF×LCM

4032=12×LCM

LCM=4032/12=336

13. given

HCF=9,LCM=270

first number=45

solution

product of two numbers= HCF×LCM

45× second number=9×270

second number=9×270/45=54

hence required number= 54

14. HCF of 180 and 336