12. If the product of two numbers is 4032 and their HCF is 12, find their LCM.
and LCM of two numbers are 9 and 270 respectively. If one of the
numbers is 45, find the other number
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hii m8
1)solution
product of two no=LCM ×HCF
4032. =LCM×12
LCM=4032/12
=336
2) product of two no =LCM×HCF
45×other no=9×270
other no=9×270/45
=54 answer.
Thankyou
mansi042:
Patna
14 and half
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