12. If the resultant is equal to 0.6 times the magnitude of two equal forces
then the angle between the forces is nearer to
?
Answers
Given Info : the resultant is equal to 0.6 times the magnitude of two equal forces.
To find : The angle between the forces is nearer to ..
solution : let magnitude of each force is F
then, resultant, F' = 0.6 F
resultant of two vectors can be given as R = √(A² + B² + 2AB cosθ)
here, A = F , B = F and R = 0.6 F
so, 0.6F = √(F² + F² + 2F² cosθ)
⇒(0.6F)² = 2F² + 2F² cosθ
⇒0.36F² = 2F² + 2F² cosθ
⇒0.36 = 2 + 2cosθ
⇒0.36 - 2 = 2cosθ
⇒cosθ = -1.64/2 = -0.82
⇒θ = cos¯¹(-0.82) ≈ 145°
Therefore the angle between forces is 145°
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