Question

12. If (x+2)(x+3)-(x-1)(x+4)=0, then the value of
xis
5
-5
1/2
1/5​

Answer 1

Step-by-step explanation:

5 Is not the value. ✅

-5 Is the value ✅

Answer 2

Answer:

x = -5

Step-by-step explanation:

(x+2)(x+3) - (x-1)(x+4)=0

$(x^{2} + 5x + 6) - (x^{2} + 3x - 4)$ = 0

$x^{2} + 5x + 6 - x^{2} -3x + 4$ = 0

2x + 10 = 0

2x = -10

x = -5