Question

12. If x/2 = y/3 = k and x + y = 90°, then angles x,y are
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Answer 1

Required Answer:-

Given:

• x/2 = y/3 = k
• ∠x + ∠y = 90°

To find:

• ∠x and ∠y

Solution:

Given,

➡ x/2 = y/3 = k

➡ x = 2k ....(i)

➡ y =3k ....(ii)

It's given that,

➡ ∠x + ∠y = 90°

➡ 2k + 3k = 90°

➡ 5k = 90°

➡ k = 90°/5

➡ k = 18°

Now,

➡ ∠x = 2k

➡ ∠x = 2 × 18°

➡ ∠x = 36°

Again,

➡ ∠y = 3k

➡ ∠y = 3 × 18°

➡ ∠y = 54°

So,

➡ ∠x = 36°

➡ ∠y = 54°

Verification:

Let us verify our result.

When ∠x = 36° and ∠y = 54°,

∠x + ∠y

= 36° + 54°

= 90°

Also, we will check if x/2 = y/3 = k

x/2 = 36°/2 = 18°

y/3 = 54°/2 = 18°

So,

x/2 = y/3 = k

Hence, our answer is correct (Verified)

Answer:

• ∠x = 36°
• ∠y = 54°

Answer 2

Step-by-step explanation:

given:

•x/2 =y/3 =k

•angle x + angle y =90°

to find

•angle x angle y

solution

given

=> x /2 = y/3=k

x =2k ...... ( 1 )

y =3 k ......(ll)

angle x + angle y =90 °

2k +3k = 90°

5k =90°

k = 90 / 5

k = 18

now

angle x = 2k

angle x = 2× 18°

angle x =36°

again

angle y = 2 k

angle y = 3×18°

angle y = 54 °

so

angle x = 36

angle y =54