Question

12. If x2 – x-1=0, then the value of x^3 – 2x +1 is






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Answer 1

Answer:

0multiply with (x-1) both sides:(x-1)(x² + x + 1) = (x-1) 0 x³ - 1 ... IF x2+ x+1=0 then find (x3+1/x3)3. 2 ... y^2=a² -b²÷a^2+b^2If x = 3, y = 4 and b = 5, find the positive value of a.

Step-by-step explanation:

0multiply with (x-1) both sides:(x-1)(x² + x + 1) = (x-1) 0 x³ - 1 ... IF x2+ x+1=0 then find (x3+1/x3)3. 2 ... y^2=a² -b²÷a^2+b^2If x = 3, y = 4 and b = 5, find the positive value of a.

Answer 2

0multiply with (x-1) both sides:(x-1)(x² + x + 1) = (x-1) 0 x³ - 1 ... IF x2+ x+1=0 then find (x3+1/x3)3. 2 ... y^2=a² -b²÷a^2+b^2If x = 3, y = 4 and b = 5, find the positive value of a.

Step-by-step explanation:

0multiply with (x-1) both sides:(x-1)(x² + x + 1) = (x-1) 0 x³ - 1 ... IF x2+ x+1=0 then find (x3+1/x3)3. 2 ... y^2=a² -b²÷a^2+b^2If x = 3, y = 4 and b = 5, find the positive value of a.