Math, asked by surbhisinghrajput, 1 year ago

12. In a bag, there are balls of three colours - white,
black and green. The ratio of the number of
white and black balls is 3 : 4. The ratio of the
number of black and green balls is 3: 5. Which of
the following can be a possible value of the total
number of white and green balls in the bag?
(A) 42 (B). 32 C) 58 (D) 41​

Answers

Answered by Anonymous
6

Answer:

hope it helps you........

Attachments:

surbhisinghrajput: Thanks for explaining me...but one thing we get W+G= 29G/20 but how u got possible value 58?? did u multiply 29*2 and yes then why can u plz??
surbhisinghrajput: Thanks for explaining me...but one thing we get W+G= 29G/20 but how u got possible value 58?? did u multiply 29*2 and yes then why can u plz??
Anonymous: value of g can 0 1 2 3......
Anonymous: 20 40 60
Anonymous: so put g = 20 we got 29
Anonymous: not in the answer
Anonymous: now put 40 we got 58
Anonymous: that's it
Answered by vinod04jangid
0

Answer:

C) 58

Step-by-step explanation:

Given:- Ratio of the number of white and black balls is 3 : 4.

             Ratio of the number of black and green balls is 3: 5.

To Find:- Total number of white and green balls in the bag.

Solution:-

Let' denote the number of white balls with w, black balls with b and green balls with g.

According to the question,

                    \frac{w}{b} =\frac{3}{4}  ---------- (1)   and     \frac{b}{g} =\frac{3}{5}  ------------ (2)

So, according to equation (1) b = \frac{4w}{3}   , and

according to equation (2)  b = \frac{3g}{5}.

\frac{4w}{3}  = \frac{3g}{5}

w = \frac{9g}{20}

w +g = \frac{9g}{20} + g

w+g = \frac{29g}{20}

As we know, number of balls can never be a whole number.

So, to make \frac{29g}{20} , a integer, g can be 20, 40,....

Therefore, number of white balls and green balls will be 29, 58,....

The correct answer is C) 58.

#SPJ2

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