Question

12. In a right-angled triangle, if base is 7cm and hypotenuse is 13cm, find its area.​

Answer 1

» Let ABC is a right angled triangle.. right angle at B.

$\angle{B}$ = 90°

Base (B) = 7 cm

Hypotenuse (H) = 13 cm.

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• We have to find the area of triangle and it's perpendicular too.

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Solution:

We know that

H² = P² + B² (By Pythagoras theoram)

=> (AC)² = (AB)² + (BC)²

=> (13)² = (AB)² + (7)²

=> 169 = (AB)² + 49

=> (AB)² = 169 - 49

=> (AB)² = 120

=> AB = √120 cm

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Area of triangle = $\dfrac{1}{2}$ × base × height

=> $\dfrac{1}{2}$ × BC × AB

=> $\dfrac{1}{2}$ × 7 × √120

=> $\dfrac{7\sqrt{120}}{2}$ cm²

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