Question

12. In AABC, AB = AC = 7.5 cm and BC = 9 cm. The height AD
from A to BC, is 6 cm. Find the area of AABC. What will be the
height CE from C to AB?​

Answer 1

Answer:bro remember the formula of area of isocels TRIANGLE = b/2 √a2 - b2/4

Step-by-step explanation:

here a = equal side b = third side put value find the answer.

if AD AND CD is Perpendicular then simply use 1/2 base x height

and phythagorus theorem to find the length of CE

PERPENDICULAR in AN ISOCELES TRIANGLE IS THE MEDIAN OF THAT TRIANGLE . HOPE IT HELPS

Answer 2

Answer:

PLEASE MARK ME AS BRAINLIEST..

Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM

HOPE THIS ANSWERS WILL BE HELP U.