Question

12. In Angle ABC, if 3 ∆A = 6∆B = 8∆C, calculate the measures of ∆A, ∆B and ∆C. and the ans is 1 st angle 96 2nd angle 48 3rd angle 36​

Answer 1

Answer:

Step-by-step explanation:

as 3A=6B

so A=2B  

and similarly 8C=6B which gives C=3B/4

now A+B+C=180  (angle sum property)

by putting A=2B and C=3B/4  we get

2B+B+3B/4=180  (now lets take 4 as L.C.M)

(8B+4B+3B)/4=180

15B=720 which gives B=48

and as we know A=2B  so A=2×48=96

and C=(3×B)/4=(3×48)/4=36

so we get A=96,B=48 and C=36