Question

12. In November 2013, the price of petrol was x cents
per litre.
(i) Write down an expression, in terms of x,
for the number of litres of petrol that could be
bought with $60 in November 2013.
In December 2013, the price had increased by
10 cents per litre.
(ii) Write down an expression, in terms of x,
for the number of litres of petrol that could be
bought with $60 in December 2013.
(iii) Given that an additional 1.3 litres of petrol
could be bought in November 2013 than in
December 2013, form an equation in x and
show that it reduces to r? + 10x - 42 000 = 0.
(iv) Solve the equation x? + 10x - 42 000 = 0.
(v) Find the number of litres of petrol that could
be bought with $34 in December 2013.
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Answer 1

Answer:

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