12. In penta-1,3 - diene, 2nd CH—3rd CH bond length is less than the expecter
value. Explain.
Answers
Answered by
2
Answer:
Explanation:
CH2=CH−CH=C+H2↔C+H2−CH=CH−C−H2→C−H2−CH=CH−C+H2
Due to resonance, the C2−C3 bond has a bond length between C-C (single) bond and C=C (double) bond i.e., 146 pm.
Similar questions