Question

12. In successive experimental measurements, the
refractive index of glass turned out to be 1.54. 1.45,
1.53, 1.56, 1.44 and 1.54. Compute (i) mean refractive
index, (ii) mean absolute error, Cit) fractional error
and (iv) percentage error. (v) Express the refractive
index with the error limits.​

Answer 1

Answer:

11th

Physics

Units and Measurement

Errors in Measurement

In an experiment, the refra...

PHYSICS

In an experiment, the refractive index of glass was observed to be 1.45,1.56,1.54,1.44,1.54 and 1.53. Calculate relative error.

MEDIUM

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ANSWER

Mean value of measurements = n = Sum of all measurements / 6 = 1.51

Absolute error of each measurement = | measurement - mean value |

=0.06,0.05,0.03,0.07,0.03,0.02 (only absolute value)

Mean value of Absolute error =Δn=0.043 (arithmatic mean of above )

When you report refractive index from the experimnet , you say :1.51+−0.043

Relative error=

n

Δn

=

1.51

0.043

=0.0285