Question

12.
In the circuit the current flowing through 10 ohm resistance
20 V
1012
0.52
1512
Who
(a) 12 A
(c) 0.8 A
(b) 1.2 A
(d) 0.4 A​

Answer 1

Answer:

b) 1.2 A

Explanation:

detailed calculation is in the picture

Answer 2

Answer:

option (b)    1.2 A is the correct answer

Explanation:

Given:

V = 20 volts

Req = 1/R1 + 1/R2 + R3 + R4  ( 10ohms & 15 ohms are in parallel & 3 ohms & 0.5 ohms are in series)

1/Rp = 1/10 + 1/15            

1/Rp = 3 + 2/30

1/Rp = 5/30

Rp = 30/5

Rp = 6 ohms

Rs =  3 + 0.5= 3.5 ohms

Req = 6 + 3.5 = 9.5 ohms

According to Ohm's law,

V = IR

Or , I = V/R

I = 20/ 9.5 Amperes.

Let current across R1 is i1 & across R2 is i2

Now, Currrent across R1 & R2 is

i1 x 10 = i2 x 15  

i2 = 10/15 X i1

i2 = 2/3 i1

i1 + i2 = Req

i1 + 2/3 i1 = 20/9.5

5/3 i1 = 20/9.5

Or, i1 = 20 x 3 / 5 x 9.5

i1 = 4 X 3 / 9.5

i1 = 12/9.5

i1 = 1.2 A

Thus, the current flowing across the 10 ohms resistor is approximate 1.2A

Ohm's Law:

Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.

V ∞ I

V = R I

• V = potential difference
• R = resistance

• I = currrent