Question

12. In the figure 2B-90", ZA = 2C and BC-10cm, then find the value of tan 45º.
А
10cm​

Answer 1

Answer:

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Answer 2

$\underline{\underline{\maltese\: \: \textbf{\textsf{Question}}}}$

In ∆ABC, B=90°, A= C and BC=10cm, then find the value of tan 45º.

$\underline{\underline{\maltese\: \: \textbf{\textsf{Answer}}}}$

• B = 90°
• A = C = 45°

also,BC = AB ( A = C )

Hence,

$\sf \: tan \: \theta = \frac{perpendicular}{base} \\ \\ \sf \: tan \: \theta = \frac{ab}{bc} \\ \\ \sf \: tan \: \theta= \frac{bc}{bc} \: \: \: \: (ab=bc) \\ \\ \sf \: tan \: \theta=1 \\ \\ \sf tan \: \theta = tan45° \\ \\ \sf \: \theta=45° \\ \\ \sf \: so,tan \: 45°=1$