Question

12. In the figure, ABC is a right-angled triangle. Find
(i) the area of AABC
(ii) the length of AC
(iii) the length of BD correct to two places of decimal.​

Answer 1

Step-by-step explanation:

(i) |∆ABC| = [1/2 × AB × BC] sq.cm

= [1/2 × 9 × 40] sq.cm

= 180 sq.cm

(ii) AC = √(9² + 40²) cm

= √(81 + 1600) cm

= √1681 cm

= 41 cm

(iii) [1/2 × AB × BC] = [1/2 × AC × BD]

or, AB × BC = AC × BD

or, 9 × 40 = 41 × BD

so,

BD = 360/41 cm

= 8.7804878048......... cm

≈ 8.78 cm

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Answer 2

Step-by-step explanation:

You can find your answer in the attached picture.