Math, asked by subhasinisahoo538, 5 months ago

12. In the figure given below, ZB = ZD=
90° and AB = DE. Prove CD = BC.

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Answered by Anonymous

1

Answer:

Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO ..

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