Question

12. In the given circuit, with steady current, the potential
drop across the capacitor will be
R
w
11
mm
R
th
WW
R
27
3V
2
(3) V
(2)
(1)
(4) 2V
wir
E​

Answer 1

ANSWER

As the capacitors offer infinite resistance to steady current so no current will flow through capacitor branch. Now the equivalent circuit is shown in the figure and apply Kirchhoff's voltage law, we get

2V−V=2RI+RI⇒I=

3R

V

Voltage across AB is V

AB

=V+RI=V+R(V/3R)=

3

4V

also V

AB

=V+V

C

where V

C

= potential across C.

or (4V/3)=V+V

C

∴V

C

=

3

4V

−V=

3

V

Answer 2

As the capacitors offer infinite resistance to steady current so no current will flow through capacitor branch. Now the equivalent circuit is shown in the figure and apply Kirchhoff's voltage law, we get

2V−V=2RI+RI⇒I=

3R

V

Voltage across AB is V

AB

=V+RI=V+R(V/3R)=

3

4V

also V

AB

=V+V

C

where V

C

= potential across C.

or (4V/3)=V+V

C

∴V

C

=

3

4V

−V=

3

V