Question

А
12. In the given figure, a triangle ABC
is drawn to circumscribe a circle of
radius 3 cm such that the segments
BD and DC into which BC is divided
by the point of contact D, are of
lengths 6 cm and 9 cm respectively. If
the area of AABC = 54 cm? then find
the lengths of sides AB and AC.
​

Answer 1

Answer:

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nhyu9jgg

Answer 2

Step-by-step explanation:

54=(x+15)(9)(6)(x)

Squaring both sides, we have

542=54x(x+15)

x2+15x−54=0

Solve this quadratic equation and find the value of x.

x2+18x−3x−54=0

x(x+18)−3(x+18)=0

(x−3)(x+18)=0

Either x=3 or x=−18

But x cannot be negative.

So, x=3

Answer :-

AB=x+6=3+6=9cm

AC=x+9=3+9=12cm