Question

12. In the given figure AABC ||| ADEF, ABC=DEF =60° then the length of DF is
4.8 cm b. 24 cm
C. 4.6 cm d. 1.3 cm
​

Answer 1

Answer:

Given, △ABC∼△DEF

Therefore,

DE

AB

=

EF

BC

=

FD

CA

So,

18

2x−1

=

3x+9

2x+2

=

6x

3x

Now taking

18

2x−1

=

6x

3x

, we have

18

2x−1

=

2

1

or 4x−2=18 or x=5

Therefore, AB=2×5−1=9,

BC=2×5+2=12,CA=3×5=15,

DE=18,EF=3×5+9=24

and FD=6×5=30

Hence,

AB=9cm,BC=12cm,CA=15cm,DE=18cm,EF=24cm and FD=30cm