12) In the given figure, FB is perpendicular
to DBC and AEL BC. Also, FBA = 709
and ZEAC = 25°. Find ZFBD and the
three angles of the triangle ABC. Give
explanations for your answers.
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ABE=90-70
=20
FBD=180-90
=90
ABE=20(AS I TOLD PREVIOUSLY)
BAC IS BISECTED BYA LINE SO ITS TWO PARTS ARE EQUAL
SO BAC=25*2=50
ECA=180-(50+20)
=110
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