12. In the given figure, find the value of y. 200° By 27/88°
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Answer:
36
Step-by-step explanation:
Let the given triangle be ABC such that ∠ABC=36. A line through C meets AB at D.
Now, In △DBC,
DB=DC (Given)
hence, ∠DBC=∠DCB=36∘ (Isosceles triangle property)
Sum of angles of triangle = 180
∠DBC+∠DCB+∠CDB=180
36+36+∠CDB=180
∠CDB=108
Now, ∠ADC=180−∠ADB
∠ADC=180−108
∠ADC=72∘
in △ADC,
∠ADC=∠DAC=72∘ (Isosceles triangle property, AC= CD is given)
Sum of angles = 180
∠ADC+∠CAD+∠ACD=180
72+72+x=180
x=180−144
x=36∘
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Answer:
12. In the given figure, find the value of y. 200° By 27/88°
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