Question

12. In the given figure line XY and MN intersect at O if ∠POY=90° and a:b= 2:3, find c.​

Answer 1

Answer:

Correct option is

C

126

o

In the given figure,

∠POY=90

∘

∠POX+∠POY=180

∘

( Linear pair )

∠POX+90

∘

=180

∘

⇒∠POX=90

∘

a:b=2:3

Let a=2x

∘

and b=3x

∘

∠POX=a+b=5x

90

∘

=5x

⇒x=18

.

∠MOX=b=3x=54

∘

∠MOX+∠NOX=180

∘

( Linear pair)

b+c=180

∘

54

∘

+c=180

∘

c=180

∘

−54

∘

=126

∘

Answer 2

Step-by-step explanation:

$∠pox = 90° \\ a:b= 2:3 \\ ∠pox =a + b \\ \: ∠pox = 2x + 3x \\ 90° = 2x + 3x \\ 90° = 5x \\ x = \frac{90°}{5} = 18° \\ a = 2x = 2 \times 18 = 36° \\ b = 3x = 3 \times 18 = 54° \\ ∠mon = 180° \\ b + c = 180° \\ 54° + c = 180° \\ c = 180° - 54° = 126°$

hope it is helpful for you