12. In ∆, we draw a line parallel to . If, = 1.28, = 2.56 and = 0.64 then is equal to (a) 1.28cm (b) 2.56cm (c) 0.64cm (d) 0.32cm
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Step-by-step explanation:
The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.
It is given that PQ=1.28 cm, PR=2.56 cm, PE=0.18 cm and PF=0.36 cm.
We find the following:
EQ=PQ−PE=1.28−0.18=1.10 cm
FR=PR−PF=2.56−0.36=2.20 cm
Using the basic proportionality theorem, we have
EQ
PE
=
1.10
0.18
=0.1636
FR
PF
=
2.20
0.36
=0.1636
Since
EQ
PE
=
FR
PF
Hence, EF is parallel to QR.
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❄️ ANSWER ❄️
- A.1.28 cm
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