Question

12 iron rod of radius 2.5 cm and length 1.75m were screwed up to make a framework for 'Vedi' for the marriage ceremony.find the cost of decorating the framework with flowers at the rate of ₹200 per sq m.
​

Answer 1

Here,

Length of each rod, l = 1 m

Area of cross-section of each rod,

Resistivity of copper rod,

Resistivity of iron rod,

Resistance of copper rod,

and resistance of iron rod,

As copper and iron rods are connected in series, therefore equivalent resistance is

Have a nice day mate ❤️

Answer 2

Step-by-step explanation:

Given:-

12 iron rod of radius 2.5 cm and length 1.75m were screwed up to make a framework for 'Vedi' for the marriage ceremony.

To find:-

find the cost of decorating the framework with flowers at the rate of ₹200 per sq m.

find the cost of decorating the framework with flowers at the rate of ₹200 per sq m.Solution:-

Radius of the Iron rod=(r)=2.5 cm

Length of the Iron rod=(h)=1.75 m

we know that 1 m=100 cm

=>h=1.75×100=175 cm

Curved surface area of the one Iron rod

=Curved surface area of the cylinder

=2πrh sq.units

=>2×22×2.5×175/7

=>2×22×2.5×25

=>2×22×25×25/10

=>22×125

=>2750 cm²

Curved Surface Area of each iron rod=2750 cm²

Curved Surface Area of 12 Iron rods

=>12×2750 cm²

=>33000 cm²

we know that 1m²=10000 cm²

=>1cm²=1/10000 m²

=>33000 cm²=33000/10000

=>33000 cm²=3.3 m²

Curved surface area of 12 Iron rods =3.3 m²

Cost of decorating the frame work with flowers per 1m² =Rs.200

Cost of decorating the frame work with flowers per 3.3 m²

=3.3×200

=>Rs. 660

Answer:-

the cost of decorating the framework with flowers of Vedi =Rs.660