Question

12: It a= pq², b=p3q then Find LCM (a,b) and
HOE (a,b)​

Answer 1

Step-by-step explanation:

Given -

• a = pq² and b = p³q

To Find -

• HCF(a,b) and LCM(a,b)

Now,

pq² = p × q × q

p³q = p × p × p × q

Then,

HCF(a,b) = pq

LCM(a,b) = p³q²

Verification :-

• LCM × HCF = product of two numbers

→ pq × p³q² = pq² × p³q

→ p^4q³ = p^4q³

Hence,

Verified...

It shows that our answer is absolutely correct.

Answer 2

$\large{\underline{\bf{\purple{correct\:Question:-}}}}$

If a = pq², b = p³q then find LCM (a,b) and HCF(a,b).

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$\large{\underline{\bf{\green{Given:-}}}}$

✰a = pq²

✰ b = p³q

$\large{\underline{\bf{\green{To\:Find:-}}}}$

✰ we need to find the LCM and HCF of two numbers.

$\huge{\underline{\bf{\red{Solution:-}}}}$

we know that a = pq², and b = p³q

So,

a = pq² = p × q × q

b = p³q = p × p × p × q

So,

✰ HCF(a,b) = pq

✰ LCM (a,b) = p³q²

Now, Varification:-

we know that,

LCM(a,b) × HCF(a,b) = product of two numbers

$: \implies \sf\:$pq × p³q²= pq² × p³q

$: \implies \sf\:$p⁴q³ = p⁴q³

Hence varified

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