Question

12. It takes 1 3/4 of cloth to make a pair of trousers. If the cloth needed to make 10 pairs of
trousers is cut out of a 20-m length of cloth, what length of cloth will be left?​

Answer 1

Given :-

• Cloth need to make a pair of Trousers = 1(3/4) .
• For 10 pairs cloths used = 20m length.

To Find :-

• what length of cloth will be left ?

Solution :-

→ Cloth need to make a pair of Trousers = 1(3/4) = (7/4) m

→ Cloth need to make 10 pair of Trousers = 10 * (7/4) = (35/2) m .

And,

→ Total cloths Present = 20m.

→ After making 10 pair of Trousers cloth left = 20 - (35/2)

= (40 - 35) /2 = (5/2) m. = 2(1/2)m. (Ans.)

Hence, After making 10 pairs of Trousers from a cloth of Length 20m, 2(1/2) m of cloth Left.

Answer 2

Answer:

$:\implies\text{One Pair of Trouser} \:\sf = 1{}^{3}\!/{}_{4}\\\\:\implies\text{One Pair of Trouser} \:\sf = \dfrac{7}{4}\\\\:\implies\text{Ten Pair of Trouser} \:\sf = \dfrac{7}{4} \times 10\\\\:\implies\text{Ten Pair of Trouser} \:\sf = \dfrac{7}{2} \times 5\\\\:\implies\text{Ten Pair of Trouser}\:\sf = \dfrac{35}{2}$

$\rule{150}{1}$

$\boxed{\bf{\mid{\overline{\underline{\bigstar\:According\:to\:the\:Question :}}}}\mid}$

$\dashrightarrow\sf\:\:Cloth\:Left=Total-Cloth\:Used\\\\\\\dashrightarrow\sf\:\:Cloth\:Left=20-\dfrac{35}{2}\\\\\\\dashrightarrow\sf\:\:Cloth\:Left=\dfrac{(40-35)}{2}\\\\\\\dashrightarrow\sf\:\:Cloth\:Left=\dfrac{5}{2}\\\\\\\dashrightarrow\:\:\underline{\boxed{\sf Cloth\:Left=2{}^{1}\!/{}_{2} \:m}}$

⠀

$\therefore\:\underline{\textsf{Length of cloth left will be \textbf{2 {}^{\text1}\!/{}_{\text2} m}}}.$