Question

12, Juan 12
Find the H.C.F of following numbers:
) 9, 27 and 135
b) 42, 63 and 105​

Answer 1

Answer:

1st question

HCF is 9 because only 9 is common.

2nd question

HCF is 21 3 and 7 is common

Answer 2

Answer:

9= 1×3×3

27=1×3×3×3

135=1×5×3×3×3

Therefore ,3×3

HCF=6