12 L of H₂ and 11.2 L of Cl₂ are mixed and exploded. Find the composition by volume of mixture.
(a) 11.2, 11.2, 22.4
(b) 0.8, 0, 22.4
(c) 0.8, 0.8, 22.4
(d) 0.8, 11.2, 22.4
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The total volume of the two gases = 11.2 + 12 liters
= 23.2 liters
23.2 - 22.4 = 0.8 liters (left over or excess hydrogen).
Answer A✔✔✔✔
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Answer:
12 L of H₂ and 11.2 L of Cl₂ are mixed and exploded. Find the composition by volume of mixture.
(a) 11.2, 11.2, 22.4
(b) 0.8, 0, 22.4
(c) 0.8, 0.8, 22.4
(d) 0.8, 11.2, 22.4z✔️
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