Question

12. Let a(b - c)x2 + b(c - a)x + c(a - b) = 0 has two equal roots. The true relation is ---


(a) 1/a +1/b = 2/c
(b) 1/a+ 1/c = 2/b
(c) 1/b +1/c = 2/a
(d) N.O.T.​

Answer 1

Answer:

NOT

Step-by-step explanation:

a(b-c)2+b(c-a)x+c(a-b)=0

=>2ab-2ac+bcx-xab+ca-cb=0

=>2x(ab-ab)-2(ac-ac)+x(cx+cx)=0

=>2x-2+x=0

=>3x=2

=>x=2/3