Question

12. lim cot 2x sin 6x
solve using lhoptal rule
​

Answer 1

Answer:

it must be 0.333 if lim of x tends to 0

Step-by-step explanation:

L'Hôpital's rule or L'Hospital's rule provides a technique to evaluate limits of indeterminate forms. Application of the rule often converts an indeterminate form to an expression that can be easily evaluated by substitution.

L'Hôpital's rule:

lim f(x)/g(x)

x-->0

putting f(x) = cot 2x and g(x)= sin6x

derivatives of cot x = -csc x and sin x = cos x

putting the limit x-->0 we found 1/1

we found, 2cscx/6cosx

which will become

2/6*1/1 = 0.333