Question

12. Line sgements AB and CD intersect at O such that AC || DB. If ZCAB = 45° and ZCDB = 55°, then ZBOD = (a) 100° (b) 80° (c) 90° (d) 135°​

Answer 1

Answer:

OBD=CAB

OBD=55

Using Angle sum Property of triangle

In∆ODB

OBD+ODB+BOD= 180

55+45+DOB= 180

BOD=180-100

BOD= 80

Thus BOD=80

Answer 2

Answer:

Answer IS B)- 80°

Step-by-step explanation:

It Is A 'Z' So There IS A Line Forming Who se Angle Is 180°. So Angle ZBOD = 80°.

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