Question

12. Lines x-2y=0 and 5x+4y-
20=0 are​

Answer 1

Answer:

intersecting

Step-by-step explanation:

x-2y=0

X= 0,2,4

Y= 0,1,2

5x-2y-20=0

X=0,2,4

Y=10,5,0

put this value on graphs then lines are intersecting each other ..............

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Answer 2

Given,

Lines x-2y=0 and 5x+4y-20=0.

To find,

Whether intersecting or not and if intersecting then the point of intersection.

Solution,

Equation of first line = x - 2y = 0

Equation of Second Line = 5x + 4y - 20 = 0

Since,

⇒   x - 2y = 0

⇒   x = 2y

Put x = 2y in another equation

⇒   5x + 4y - 20 = 0

⇒   5(2y) + 4y - 20 = 0

⇒   10y + 4y - 20 = 0

⇒    14y - 20 = 0

-20 will shift from the left-hand side of the equation to the right-hand side of the equation and its sign would change from -20 to +20.

⇒   14y = 20.

⇒   y = 20/14

⇒   y = 10/7

⇒   And we had x = 2y,

⇒   x = 2(10/7) = 20/7.

Hence, the lines  Lines x-2y=0 and 5x+4y-20=0. are intersecting and they would intersect at (20/7,10/7)