Question

12 litreof h2 and 11.2 litre of cl2 are mixed and exploded .the compostion of volume of mixture is

Answer 1

Ideal gas law states that 1 mole of an ideal gas occupies a volume of 22.4 liters.

Having this in mind, you can easily calculate the number of moles of each of the gases using their volumes given.
 
This can be done as follows: 

If 22.4 liters of a gas = 1 mole
Then moles of 12 liters of H₂ will be = 1 × 12/22.4 = 0.54 moles

(Note: When converting from volume to moles divide the volume by the molar volume constant which is 22.4 L)

If 22.4 L = 1 mole 
   11.2 L = 1 mole × 11.2/24 = 0.5

(Note: When converting from volume to moles divide the volume by the molar volume constant which is 22.4 L)
  
Find the limiting agent of the reaction:

The reaction between the 2 gases is as follows: 

          H₂ + Cl₂ -----------------> 2HCl

Mole ratio is 1:1:2

Therefore Cl₂ is the limiting reagent - as 1 mole of H₂ requires 1 mole of Cl₂ to form 2 moles of HCl.

We use the moles of the Cl₂ to find the volume of the HCl.

In the reaction the mole ratio is 1:1:2....

Therefore, 0.5 moles of the Cl₂ will give 1 mole of HCl

Hence calculate the volume of 1 mole of HCl

using ideal gas law, 1 mole of HCl will occupy 22.4 liters by volume.

The total volume of the two gases = 11.2 + 12 liters
                                                       =  23.2 liters
23.2 - 22.4 = 0.8 liters (left over or excess hydrogen).

Therefore the composition of volume of mixtures is 22.4 liters of HCL and 0.8 liters of H₂

Answer 2

Hope this helps u .........